(x^2-4)(7x+1)=0

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Solution for (x^2-4)(7x+1)=0 equation: 


Simplifying
(x2 + -4)(7x + 1) = 0

Reorder the terms:
(-4 + x2)(7x + 1) = 0

Reorder the terms:
(-4 + x2)(1 + 7x) = 0

Multiply (-4 + x2) * (1 + 7x)
(-4(1 + 7x) + x2(1 + 7x)) = 0
((1 * -4 + 7x * -4) + x2(1 + 7x)) = 0
((-4 + -28x) + x2(1 + 7x)) = 0
(-4 + -28x + (1 * x2 + 7x * x2)) = 0
(-4 + -28x + (1x2 + 7x3)) = 0
(-4 + -28x + 1x2 + 7x3) = 0

Solving
-4 + -28x + 1x2 + 7x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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